> Additionally, when plane speeds up, more drag is produced, slowing it down.
Wait, is it speeding up here or slowing down? Slowing down means deceleration, speeding up is acceleration, and it can't be doing both at the same time.
> When the plane slows down, it produces less drag, allowing to to pick up more speed.
Same deal?
I think what he's getting at is that drag increases with the square of speed, but it's a very confusing way of explaining it.
A common equation you will find in aerodynamics texts is:
Drag = 1/2 * fluid density * velocity^2 * C_d * Ref. Area
It approximates the drag experienced by objects as they move within a fluid (atmosphere). You can see that drag is proportional to the square of velocity, so going twice as fast induces 4 times the drag.
Ergo, when you speed up, you produce a lot more drag. This will slow you down until you reach an equilibrium between thrust and drag (unless you apply more thrust).
Wait, is it speeding up here or slowing down? Slowing down means deceleration, speeding up is acceleration, and it can't be doing both at the same time.
> When the plane slows down, it produces less drag, allowing to to pick up more speed.
Same deal?
I think what he's getting at is that drag increases with the square of speed, but it's a very confusing way of explaining it.