Also, I discovered to my surprise that the Download links still work - in the literal, upstream, sense. You can strip off the Web Archive prefix, request the direct image links from Google, and they promptly download (because of "content-disposition: attachment"). How interesting (at the very least), lol.
That is a nice story about open source to the sad but not so bitter sounding (BOO-YAH!) end.
I am not a user (or even Gnome user), but FWIW, I looked and Adrian's eog_window_cmd_copy_image is still there almost 11 years later, only renamed in a minor way ("cmd" -> "action").
I am no expert on its churn, but the Eye Of Gnome project seems still quite active (last commit yesterday). That file src/eog-window.c itself has already had more commits since his patch than before it.
{ Not to suggest that code durability/quality is (or was) the whole point, but I thought being less "tears in rain" than it might have been took the inspirational factor up a notch and so seemed worth sharing here. }
Sorry for your loss. Lost mine when I was 17, I know the feeling. Hope the "Easter egg" brings you some comfort.
A long time ago, during a night I couldn't sleep, I started thinking on the simplest way to calculate the volume of a torus without resorting to integrals. After a time I found a way to "turn it into a cylinder without changing its volume". Then went to my father's copy of "Simmons' Calculus with analytic geometry" to check my idea. How surprised was me to see that my father had had EXACTLY the same idea and left it written on the margin of the book!
That moment I saw how careful he was to model my way of thinking to be so similar to his. I'll be eternally grateful for that.
Hmm. Thinking about it as an integral of cross sections, the torus is just a cylinder with height equal to the circumference of the circle that defines the center of its tube. And I see that that is correct, at least for non-weird tori.
> [For a non-weird torus,] The volume of this solid torus and the surface area of its torus are easily computed using Pappus's centroid theorem
> These formulas are the same as for a cylinder of length 2πR and radius r, obtained from cutting the tube along the plane of a small circle, and unrolling it by straightening out (rectifying) the line running around the center of the tube.
> The losses in surface area and volume on the inner side of the tube exactly cancel out the gains on the outer side.
Emphasis mine; that third sentence is weirding me out. Still thinking about it as an integral of cross sections, I can't see why the surface area or volume of the inner half of the torus should be different from the surface area / volume of the outer half. Are they?
