Oh, that's what Koshkin was trying to say.
> Secondly, the axiom of choice is not independent of ZFC, it's independent of ZF (assuming ZF is consistent) :).
Ah, the C stands for choice...
Oh, that's what Koshkin was trying to say.
> Secondly, the axiom of choice is not independent of ZFC, it's independent of ZF (assuming ZF is consistent) :).
Ah, the C stands for choice...